Q: Is 3 divisible by 126

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126 is divisible by 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.

Yes. 126/2 = 63. 126/3 = 42. 126/9 = 14.

126 is divisible by 2, 3 and 9 but not the other 2 126/2= 63 126/3= 42 126/9= 14

3 or 6

Yes. 126 divided by 3 is 42 42 is also divisible by 3. 42 ÷3 = 14 The prime factors of 126 are 2, 3, 3, and 7.

126 is divisible by 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126.

1, 2, 3,

yes its 126

No, it is divisible by: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126

126 is divisible by 6 and 9

A number is divisible by three is the sum of its digits (here, 1+2+6=9) is divisible by 3. So, Yes.

126/4 = 31.5

No, 120 or 126 are divisible by 6.

126,63,42,21,6,3,2,1

Yes. 126 is evenly divisible by seven.

The numbers 21 and 126 are divisible by seven. The numbers 88 and 255 have a remainder when divided, so they are not divisible by seven.

Not evenly.

Yes

To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3â†’ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3â†’ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3â†’ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3â†’ 121 is not divisible by either 2 or 3, so it is not divisible by 6

yes, its divisible by 2.

Yes.

All multiples of 126, which is an infinite number.

Two numbers: 126 and 147

Yes, 63 times.

Yes, 126/9 is 14.

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